Arrays - General Questions

When an array is passed to a function, what is actually passed?

What will be the output of the program?

#include <stdio.h>

int main(void) {
    int a[2][3] = {1, 2, 3, 4, 5, 6};
    printf("%d\n", *(*(a + 1) + 1));
    return 0;
}

What will be the output of the program?

#include <stdio.h>

int main(void) {
    int a[] = {4, 8, 15, 16, 23, 42};
    printf("%zu\n", sizeof(a) / sizeof(a[0]));
    return 0;
}

What will be the output of the program?

#include <stdio.h>

int main(void) {
    int m[2][3] = {{1, 2, 3}, {4, 5, 6}};
    int i, j, s = 0;
    for (i = 0; i < 2; i++) for (j = 0; j < 3; j++) if (i == 1) s += m[i][j];
    printf("%d\n", s);
    return 0;
}

What will be the output of the program?

#include <stdio.h>

int main(void) {
    int a[5] = {5, 3, 9, 1, 7}, i, max = a[0];
    for (i = 1; i < 5; i++) if (a[i] > max) max = a[i];
    printf("%d\n", max);
    return 0;
}